Buy Cars and Trucks in Newton, North Carolina

Cadillac : Eldorado 1992 Cadillac Eldorado
Cadillac : Eldorado 1992 Cadillac Eldorado
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$4,995.00
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Porsche : 911 Porsche 911SC Coup 1980 LOW Mileage (50, 437)
Porsche : 911 Porsche 911SC Coup 1980 LOW Mileage (50, 437)
$16,000.00
$19,500.00
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Dodge : Coronet 1966 Dodge Coronet 500 Convertible
Dodge : Coronet 1966 Dodge Coronet 500 Convertible
$8,988.00 (19 Bids)
Time Left: 1d 17h 2m

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Questions Related to newton, north cars

Provided By Y! Answers

How far from the road can I put a car port in Newton, North Carolina?
Question:
The road isn't state maintained. We were told 30 feet by a friend, not a reliable resource. But the way our house is, if that is true, 10 feet from the property line and 30 feet from the road, that means I only have that middle 20 feeet to play with.


Answer:
It would be best to either call or email the city manager so that you will get the correct information..... Todd Clark City Hall, Administration Office 401 North Main Avenue Newton, NC 28658 Phone: (828) 695-4259 FAX: (828) 465-7405 E-mail: tclark@newtonnc.gov Or check with the (CODE OF ORDINANCES CITY OF NEWTON, NORTH CAROLNA).... http://library1.municode.com/default-test/home.ht m?infobase=13848&doc_action=whatsnew

A 2500 kg car traveling to the north is slowed down uniformly from an initial velocity of 20 m/s?
Question:
A 2500 kg car traveling to the north is slowed down uniformly from an initial velocity of 20 m/s by a 6250 Newtons braking force acting opposite the car's motion. What is the car's velocity after 2.50 seconds?? PLEASE HELP!!


Answer:
F=m*a a=-6250/2500 a=-2.5 v(t)=20-2.5*t v(2.5)=20-2.5^2 13 .75 m/s j

Newton's Laws car question?
Question:
Newton's Laws car question? A car has a mass of 1400kg, it tows a trailer of mass 600kg due north along a level road at constant speed. The forces resisting the motion of the car and trailer are 400N and 100N respectively. What is the forward thrust applied to the car? What is the magnittude of the tension in the bar between the car and the trailer? If the car and trailer with the same resistance forces) have a northerly acceleration of 2.0 m squared what is: the net force applied to the trailer? The magnitude of the tension in the bar, between the car and the trailer? The forward thrust applied to the car? I have the answers...I just don't know how they got them. I got 3/5, so I just want to know how to work out the answers. If you can help me out, greatly appreciated.


Answer:
EZ forward thrust applied to the car = 400 + 100 = 500N ---answer [at constant speed] magnittude of the tension in the bar between the car and the trailer = 100 N ---answer The forward thrust applied to the car = [ 1400 + 600 ] * 2 = 4000 N ---answer The magnitude of the tension in the bar, between the car and the trailer = 4000 - 100 = 3900 N ---answer = the net force applied to the trailer ---answer

Help on high school physics question on Newton's laws and forces?
Question:
So our class is currently studying Newton's laws and forces,etc. and there are two particular questions that I have come across that I don't really understand. Help would be much appreciated. 1) The engine of a train has a mass of 50000kg. It can accelerate six railway cars having a total mass of 300000kg at 0.40m/s2. What acceleration can it give to four railway cars having a total mass of 200000 kg? 2) A delivery boy throws newspapers onto his customers' front porches. At a particular instant, the boy is riding due north at a constant speed and aims a newspaper to land on a customer's porch at Y. He throws the paper so that it travels EAST relative to his position. For the newspaper to reach its intended destination, should he throw it before he gets to, the instant he reaches, or after he has passed point X? Sorry it's very wordy, but the answer should be simple if you relate it to Newton's law of inertia and/or Newton's second law. Here's a diagram for question #2 for clarification: ^ | | | X ============= Y | (boy) | | Thanks in advance!


Answer:
1) F = m . a = 350000 . 0.4 Same force to accelerate the 250000 kg a = 350000 . 0.4 / 250000 = 0.56 m/s/s 2) He must throw BEFORE he gets to "X" . He will give the paper a speed towards "Y" while the paper will also have the bike velocity carrying it forward.

Physics - NEWTON's first law and related?
Question:
A high tech jet car speeds along the desert floor at a constant velocity of 180 miles/hr north.a) what is the net force on the jet car? the jet car hits some sand which causes a drag force on the car of 5000 N to the south. The computer instantly compensates so the jet exerts a thrust force on the car of exactly 5000 N to the north at the same time the car hits the sand. The jet car now... choose ALL that apply: slows down remains at rest maintains constant velocity moves with constant non-zero velocity speeds up moves with a changing velocity accelerates at a constant rate Newton's first law states: When the ____ on an object is zero, the object will ____ constant ____. Another way of saying this is that, if the total force on it equals zero, an object's ___ will also be zero. Is it necessary to apply a force to keep an object going in a circle at constant speed? Yes/No, because the ____ is changing/not changing.


Answer:
OK, I'll try to help you learn the principle so you can pass the test. My explanations are in (). A high tech jet car speeds along the desert floor at a constant velocity of 180 miles/hr north.a) what is the net force on the jet car? the jet car hits some sand which causes a drag force on the car of 5000 N to the south. The computer instantly compensates so the jet exerts a thrust force on the car of exactly 5000 N to the north at the same time the car hits the sand. The jet car now... choose ALL that apply: (There has been drag all along. Since the car has been going at a constant velocity, the car's jet has to be exerting an equal and opposite force to compensate for the drag. If the drag and thrust are equal and opposite there's no net force. Newton's 1st says it will stay in motion at the same speed in the absence of a net force. So now, the net force = 5000 N - 5000 N = 0.) The car maintains constant velocity moves with constant non-zero velocity (I explained all this above.) Newton's first law states: When the __ net force__ on an object is zero, the object will __maintain__ constant __velocity__. Another way of saying this is that, if the total force on it equals zero, an object's _acceleration__ will also be zero. Is it necessary to apply a force to keep an object going in a circle at constant speed? (The object will want to keep going at constant speed in a straight line because of inertia - without a net force it will do that. The force required to go in a circle is towards the center.) Yes, because the __velocity__ is changing.

Questions relating to application of Newton's 1st law?
Question:
inertia would be best described as... (CHOOSE ALL THAT APPLY) mass resistance to change in velocity the tendency to maintain constant velocity the force of gravity resistance to acceleration a force within the object a property of matter A high tech jet car speeds along the desert floor at a constant velocity of 180 miles/hr north.a) what is the net force on the jet car? ______ __(units) Is it necessary to apply a force to keep an object going in a circle at constant speed? Yes, b/c velocity is changing. a) What is the net force on an object if you exert 10 N to the right, 4 N to the left, and an additional 6 N to the left? 0 N no direction b) If the object was going 15 m/s when you began to apply the forces, how far will it go in the following 2 seconds? You are going at constant velocity in the passenger seat of a vehicle, when the driver suddenly turns to the left. Explain what you experience in this scenario and defend your response with Newton's 1st Law.


Answer:
1))) inertia would be best described as resistance to acceleration a property of matter 2)))zero 3)))Yes 4)))a))please specify the direction in which you want to calculate force b))please specify whether the body was going raght or left 5)))We experience the pseudoforce

Newtons Second Law Homework Question{Physics}?
Question:
Problem: The net force on a golf cart is 390N {N for Newtons} north.If the cart has a total mass of 270kg, what are the magnitude and direction of the cars acceleration? I am not sure how to find the magnitude and direction? I am wondering do i use the formula: a=netforce/mass? or something different?


Answer:
Newton's 2nd law F = m*a rearranging this formula gives a= F/m as you stated as the nett (resultant) force is acting due North then the cart will move due North and the acceleration will be in this direction also. Magnitude is the size: a= F/m = 390/270 = 13/9 m/s/s ans a = 13/9 m/s/s due North

newtons/vectors please help!!?
Question:
The dermolition derby is underway at the state fair , and the green car is in trouble. The red car is forcing the green car east using 1020 newtons.At the same time the blue car is forcing the green car due north using 740 newtons. Assume the green car is at 0,0. What are the compass coordinates of the tip of the resultant vector?


Answer:
I see that there is no response to your question I would advise you to go to Science & Mathematics ---> Physics you are definitely more likely to get a good answer over there. if you think my answer didn't help you, feel free to vote "no best answer", I will make sure that the answer gets deleted.

Figure this out....Newton's 1st law?
Question:
A high tech jet car speeds along the desert floor at a constant velocity of 180 miles/hr north. what is the net force on the jet car? The jet car hits some sand which causes a drag force on the car of 5000 N to the south. The computer instantly compensates so the jet exerts a thrust force on the car of exactly 5000 N to the north at the same time the car hits the sand. The jet car now... choose ALL that apply: slows down remains at rest maintains constant velocity moves with constant non-zero velocity speeds up moves with a changing velocity accelerates at a constant rate What happens?


Answer:
Hi. The car is traveling at a constant speed at first, so the forces cancel. After hitting the sand the forces again instantly balance, so: maintains constant velocity moves with constant non-zero velocity

Physics - Newton's 2nd Law?
Question:
Hey again! Another Physics problem! A car of mass 1400kg tows a trailer of mass 600kg due north along a level road at constant speed. the forces resisting the motion of the car and trailer are 400N and 100N respectively. A. I. Determine the forward thrust applied to the car II. Whats is the magnitude of the tension in the bar between the car and the trailer? B. If the car and trailer in part (a), with the same resistance forces, have a northerly acceleration of 2.0ms-2, what is: I. the net force applied to the trailer II. the magnitude of the tension in the bar between the car and the trailer III. the forward thrust applied to the car ANSWERS: A. I. 500N North II. 100N B. I. 1200N north II. 1300N III. 4500N north ANY IDEA, how the book got those answers? Thank you SO MUCH!


Answer:
A Let the tension in the rope be T. Because the trailer is going with constant speed in straight line, net force acting on it = zero. But it is given that there is resistive force acting on trailer equal to 100 N. Now tension also acts on trailer in te direction of motion. So tension, T must be equal to 100 N in te direction of motion on the trailer. Now same tension T is acting on the car opposite to direction of motion. It is also given that the resistive force acting on the car = 400 N. and car is moving with constant speed I straight line. So the thrust provided to the car must be equal to 400+100 = 500 N in the direction of motion. B I. If common acceleration is 2 m/s^2, then there must be a net force of 600x2= 1200 N acting on trailer. II. 100 N is already the restive force. So tension in the connecting bar must be 1200 +100 = 1300 N acting in the direction of motion of trailer. III. Similarly, there must be a net force of 1400x2= 2800 N. already the bar is pulling the car with 1300 N and resistive force of 400 N opposite to the direction of motion. So the thrust developed by the car acting in the direction of motion must be 2800+1300+400=4500 N